SOLUTION: Cube root[2x-4]-2=0 How do I solve for X with a cube root? Would I cube all parts of the equation, simplifying to 2x-4+8=0? Thanks in advance.

Click here to see ALL problems on real-numbers

Question 941183: Cube root[2x-4]-2=0
How do I solve for X with a cube root? Would I cube all parts of the equation, simplifying to 2x-4+8=0?
Thanks in advance.

Found 2 solutions by richard1234, stanbon:
Answer by richard1234(7193) (Show Source):
You can put this solution on YOUR website!

Cubing both sides of the equation does *not* give (or 2x-4 - 8 = 0, for that matter) -- look up binomial theorem. Cubing both sides instead gives you , which does not look as easy to solve.

A simpler way to solve is to add 2 to both sides, giving . Then cube both sides to get , or x = 6.

Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
Cube root[2x-4]-2=0
---------
(2x-4)^(1/3) = 2
----
Cube both sides to get:
2x-4 = 8
2x = 12
x = 6
-----------
Cheers,
Stan H.
----------