SOLUTION: Solve; 1.) 11x/5 = 33y/15 2.) If the ratio of a to b is 2:3,then a =2, b = 3 3.) If 6p:5q = 9:15, then p is twice as much as q

Algebra ->  Trigonometry-basics -> SOLUTION: Solve; 1.) 11x/5 = 33y/15 2.) If the ratio of a to b is 2:3,then a =2, b = 3 3.) If 6p:5q = 9:15, then p is twice as much as q      Log On


   

Question 941056: Solve;
1.) 11x/5 = 33y/15
2.) If the ratio of a to b is 2:3,then a =2, b = 3
3.) If 6p:5q = 9:15, then p is twice as much as q
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

1.)
11x%2F5+=+33y%2F15 ....cross multiply
11x%2A15+=+33y%2A5 ....both sides divide by 5
%2811x%2A15%29%2F5+=+%2833y%2A5%29%2F5....simplify
%2811x%2Across%2815%293%29%2Fcross%285%29+=+%2833y%2Across%285%29%29%2Fcross%285%29
11x%2A3+=+33y
33x+=+33y....both sides divide by 33
x+=+y

2.)
If the ratio of a to b is 2%3A3,then a+=2, b+=+3
proof:
a%3Ab=2%3A3
3%2Aa=2%2Ab is true if and only if a+=2 and b+=+3

3.)
If 6p%3A5q+=+9%3A15, then p is twice as much as q:
6p%2A15+=+9%2A5q
cross%286%292p%2Across%2815%293+=+cross%289%293%2Across%285%29q

2p%2A3+=+3%2Aq
6p+=+3q...divide by 3
2p+=+q-so,p is twice as much as q