SOLUTION: find the consecutive even integers such that four times the first minus the twice the third is equal to the second.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: find the consecutive even integers such that four times the first minus the twice the third is equal to the second.       Log On


   



Question 941031: find the consecutive even integers such that four times the first minus the twice the third is equal to the second.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let the 3 consecutive even integers be:
+n+, +n%2B2+, and +n%2B4+
--------------------------------
+4n+-+2%2A%28+n+%2B+4+%29+=+n+%2B+2+
+4n+-+2n+-+8+=+n+%2B+2+
+2n+-+8+=+n+%2B+2+
+n+=+10+
+n%2B2+=+12+
+n%2B4+=+14+
the 3 consecutive even integers are 10, 12, and 14
check:
+4n+-+2%2A%28+n+%2B+4+%29+=+n+%2B+2+
+4%2A10+-+2%2A14+=+12+
+40+-+28+=+12+
+12+=+12+
OK