SOLUTION: Jim built a rectangular shed with a total floor-surface area of 126 sq.ft. If the length is 4 feet more than twice it's width, what is the length of the shed? I have no clue.

Algebra ->  Polygons -> SOLUTION: Jim built a rectangular shed with a total floor-surface area of 126 sq.ft. If the length is 4 feet more than twice it's width, what is the length of the shed? I have no clue.      Log On


   

Question 941012: Jim built a rectangular shed with a total floor-surface area of 126 sq.ft. If the length is 4 feet more than twice it's width, what is the length of the shed? I have no clue.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+A+=+L%2AW+
+126+=+L%2AW+
+L+=+2W+%2B+4+
-----------------
By substitution:
+A+=+%28+2W+%2B+4+%29%2AW+
+126+=+2W%5E2+%2B+4W+
+2W%5E2+%2B+4W++-+126+=+0+
Divide through by +2+
+W%5E2+%2B+2W+-+63+=+0+
+%28+W+%2B+9+%29%2A%28+W++-+7+%29+=+0+ ( by looking at it )
+W+=+7+ ( can't use negative result )
-------------------
and, since:
+L+=+2W+%2B+4+
+L+=+2%2A7+%2B+4+
+L+=+18+
The length is 18 ft
-------------------
check:
+126+=+L%2AW+
+126+=+18%2A7+
+126+=+126+
OK