Question 941010: One integer is 18 more than twice another number, if their product is equal to -36, what are the integers? Give one of the two pairs of numbers for which this is true. I came up with 6 I'm not sure if I did this right.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! One integer is 18 more than twice another number,
a = 2b + 18
if their product is equal to -36, what are the integers?
a*b = -36
Therefore
b(2b+18) = -36
2b^2 + 18b + 36 = 0
simplify, divide by 2
b^2 + 9b + 18 = 0
Factors to
(b+3)(b+6) = 0
Two solutions
b = -3
b = -6
then when b = -3
a = 2(-3) + 18
a 12
when b = -6
a = 2(-6) + 18
a = 6
Give one of the two pairs of numbers for which this is true.
a=12, b=-3 or a=6, b-6
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