SOLUTION: Will Someone please help!! I don't know where to start. (I'm given the answer Scale factor = 2.12;The center is the oil drum.) But i'm not sure how to work out the problem! Oil

Algebra ->  Bodies-in-space -> SOLUTION: Will Someone please help!! I don't know where to start. (I'm given the answer Scale factor = 2.12;The center is the oil drum.) But i'm not sure how to work out the problem! Oil       Log On


   

Question 941008: Will Someone please help!! I don't know where to start. (I'm given the answer Scale factor = 2.12;The center is the oil drum.) But i'm not sure how to work out the problem!
Oil from a drum leaks into water surrounding the drum, creating a circular oil slick 100 square feet in area. Find the scale factor of the size transformation of the oil slick when it is 450 square feet in area. Round to the nearest hundredth. Where is the center of the size transformation?
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
The scale factor is done here according to length measurement. Why the 100 sq.ft. and 450 sq.ft. values were taken for reference is not explained.

r for radius of the 100 sq. ft. region,
R for radius of the 450 sq ft region,

pi%2Ar%5E2=100 and pi%2AR%5E2=450;
r=sqrt%28pi%2A100%29 and R=sqrt%28pi%2A450%29;

R%2Fr=2.12. This is the scale factor for the size transformation.

The center of the size transformation could only be assumed to be the leaking oil drum as long as it has not moved.