SOLUTION: one number exceeds another number by 6. Write these two numbers in terms of x. When twice the larger number is added to three times the smaller number, the result is 32. Find the t
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Question 940870: one number exceeds another number by 6. Write these two numbers in terms of x. When twice the larger number is added to three times the smaller number, the result is 32. Find the two numbers. Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! One number = x the other X+6
When twice the larger 2(x+6) is added to three times the smaller (3x)the result is 32. So 2(x+6)+3x=32
2x+12+3x=32 Multiply out the 2
5x+12=32 Combine
5x+12-12=32-12 Subtract 12 from both sides
5x=20
5x/5=20/5 Divide both sides by 5
x=4 ANSWER One number is 4, the other is 4+6=10
CHECK:
Twice the larger added to 3 x the smaller =32
2(10)+3(4)=32
20+12=32
32=32
