SOLUTION: Use intercepts to graph each equation. 5x - 8y = 16

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Question 94085This question is from textbook Algebra 2
: Use intercepts to graph each equation.
5x - 8y = 16
This question is from textbook Algebra 2

Found 2 solutions by bucky, jim_thompson5910:
Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
You are given the equation:
.
5x+-+8y+=+16
.
and are told to use intercepts to graph the equation.
.
The intercepts of a linear equation are the coordinate points where it crosses the y-axis and
where it crosses the x-axis. If you plot these two points, you can get the graph by using a
straight edge to draw a line that extends through these two points and beyond.
.
The coordinate point on the y-axis will have an x-value of what? When you think about it,
you can see that any point on the y-axis will have an x-value of zero. So to get the y-value
from this equation, you can set x equal to zero and solve for y. When you do set the value
of x equal to zero, the equation reduces to:
.
5%2A0+-+8y+=+16
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and the 5*0 term is equal to zero so it drops out and the equation is down to:
.
-8y+=+16
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Now you can solve for y by dividing both sides of the equation by -8 to get:
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y+=+16%2F%28-8%29+=+-2
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We now know that the graph crosses the y-axis at the point (0, -2).
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Again you have to think about the point where the graph crosses the x-axis. Any point on the
x-axis will have a y-value of zero. Therefore, in the given equation if we set y equal to zero
the value of x that we get identifies the point where the graph crosses the x-axis.
.
So set y equal to zero and the equation becomes:
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5x+-+8%2A0+=+16
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The -8*0 term multiplies out to zero and, therefore, drops from the equation, leaving just
the equation:
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5x+=+16
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You can now solve for x by dividing both sides by 5 to get:
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x+=+16%2F5
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So the x-intercept point is at (16/5, 0}
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Plot this point along with the previous y-intercept point of (0, -2) and you have two points
that you can use to draw the graph.
.
When you get done your graph should look like this:
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graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%28-5x%2B16%29%2F%28-8%29%29
.
Hope this helps you to see your way through the problem.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

5%2Ax-8%2Ay=16 Start with the given equation

Let's find the x-intercept

To find the x-intercept, let y=0 and solve for x:
5%2Ax-8%2A%280%29=16 Plug in y=0

5%2Ax=16 Simplify

x=16%2F5 Divide both sides by 5



So the x-intercept is (16%2F5,0) (note: the x-intercept will always have a y-coordinate equal to zero)

------------------

5%2Ax-8%2Ay=16 Start with the given equation

Now let's find the x-intercept

To find the y-intercept, let x=0 and solve for y:
5%2A%280%29-8%2Ay=16 Plug in x=0

8%2Ay=16 Simplify

x=16%2F-8 Divide both sides by -8



y=-2 Reduce



So the y-intercept is (0,-2) (note: the y-intercept will always have a x-coordinate equal to zero)

------------------------------------------

So we have these intercepts:
x-intercept: (16%2F5,0)

y-intercept: (0,-2)



Now plot the two points (16%2F5,0) (which is the point (3.2 ,0) in decimal form) and (0,-2)




Now draw a line through the two points to graph 5%2Ax-8%2Ay=16
graph of 5%2Ax-8%2Ay=16 through the points (16%2F5,0) and (0,-2)