SOLUTION: A baseball manager insists on having his best hitter bat fourth and the pitcher bat last.In such circumstances;how many batting orders are possibles?Please help me to solve this qu
Algebra ->
Permutations
-> SOLUTION: A baseball manager insists on having his best hitter bat fourth and the pitcher bat last.In such circumstances;how many batting orders are possibles?Please help me to solve this qu
Log On
Question 940589: A baseball manager insists on having his best hitter bat fourth and the pitcher bat last.In such circumstances;how many batting orders are possibles?Please help me to solve this question. Answer by Edwin McCravy(20060) (Show Source):
1 way to pick the 4th batter, the best hitter.
1 way to pick the 9th batter, the pitcher.
7 ways to pick the 1st batter.
6 ways to pick the 2nd batter.
5 ways to pick the 3rd batter.
4 ways to pick the 5th batter.
3 ways to pick the 6th batter.
2 ways to pick the 7th batter.
1 way to pick the 8th batter.
1 = 7! = 5040 ways
Edwin