SOLUTION: is it possible to make a regular polygon where each interior angle is exactly 9 times as large as the matching exterior angle?

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Question 940570: is it possible to make a regular polygon where each interior angle is exactly 9 times as large as the matching exterior angle?
Found 2 solutions by Alan3354, KMST:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
is it possible to make a regular polygon where each interior angle is exactly 9 times as large as the matching exterior angle?
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Yes.

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The exterior angle and the interior angle are supplementary,
meaning that they add up to 180%5Eo .
Let x be the measure of the exterior angle in degrees.
Then, 180-x is the measure of the interior angle in degrees, and
"each interior angle is exactly 9 times as large as the matching exterior angle" translates as
180-x=9x<--->180=9x%2Bx<--->180=10x<--->180%2F10=x<--->x=18 .
The exterior angle is the angle you turn around the corner/vertex, as you go around the polygon. Naturally, once you went all the way around, you have turned 360%5Eo , so the sum of the measures of all exterior angles is 360%5Eo .
All the exterior angles in a regular polygon have the same measure,
so if each exterior angle measures 18%5Eo ,
the sum of the exterior angles in the polygon is
%28180%5Eo%29%2An=360%5Eo<--->n=360%5Eo%2F180%5Eo<--->n=20 .
It is possible to make a polygon with 20 sides angles, so the answer is highlight%28YES%29 .
If we had found a result for n that was not a whole number, or was a whole number less than 3, the answer would have been no.