SOLUTION: Tom throws a ball into the air. The ball travels along a parabolic path represented by the equation
h = -8t^2 +40t
where 'h' is the height in feet and 't' is the time in seco
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h = -8t^2 +40t
where 'h' is the height in feet and 't' is the time in seco
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Question 940361: Tom throws a ball into the air. The ball travels along a parabolic path represented by the equation
h = -8t^2 +40t
where 'h' is the height in feet and 't' is the time in seconds.
What is the value of 't' where 'h' has its greatest value? What is the maximum height 'h' of the ball? Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Tom throws a ball into the air. The ball travels along a parabolic path represented by the equation
h = -8t^2 +40t
where 'h' is the height in feet and 't' is the time in seconds.
What is the value of 't' where 'h' has its greatest value? What is the maximum height 'h' of the ball?
***
h(t)=-8t^2 +40t
complete the square:
h(t)=-8(t^2-5t+25/4)+50
h(t)=-8(t-5/2)^2+50
This is an equation of a parabola that opens down with vertex at (5/2,50)
What is the value of 't' where 'h' has its greatest value? 2.5 sec
What is the maximum height 'h' of the ball? 50 ft
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