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| Question 940253:  Hello, I need help with this
 from the clues,work out the number that fits into the boxes
 (I have 5 empty boxes)
 1.   all digits are different
 2.   the first digit is odd and larger than the third digit
 3.   the fourth digit is three times the first
 4.   the final digit is the product of the second and third digit
 thank you
 Found 2 solutions by  MathLover1, Edwin McCravy:
 Answer by MathLover1(20850)
      (Show Source): 
You can put this solution on YOUR website! the first digit is
  :  could be  ,  ,  ,  ,   the first digit is
  than the  digit ...could be  ,  ,  ,  so, first digit is   since the first digit is  larger than the third  digit, then the third  digit   is
  (looking at  ,  ,  it is  ) the fourth digit is three times the first...so, it could be only
  because   
 the final digit is the
  of the second and third digit ....   remaining digits that could be the second  digit are  ,  ,  ,  and  , and only product that gives us  digit number using third digit  is  because  and the rest is same so,  the second  digit is
  and the final digit is   then we have all digits to place in empty boxes:
 the first digit is
  the second  digit is
  the third digit is
  the fourth digit is
  the final digit is
   
Answer by Edwin McCravy(20064)
      (Show Source): 
You can put this solution on YOUR website! 
_ _ _ _ _
 2.   the first digit is odd and larger than the third digit
 3.   the fourth digit is three times the first
 
 
That narrows it down to these four:
1 _ 0 3 _,   3 _ 2 9 _,  3 _ 1 9 _,  3 _ 0 9 _
 1.   all digits are different
 4.   the final digit is the product of the second and third digit
 
 
That rules out the 3rd digit being 0 or 1 for in either case it 
would make the final digit be the same as the 3rd digit, but they 
are all different. So we have
3 _ 2 9 _ 
4.   the final digit is the product of the second and third digit
The only digit not used that we can multiply by third digit 2 and 
get a different final digit is 4, and we get 4x2 = 8 for the final
digit. 
Answer: 3 4 2 9 8
Edwin 
 
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