SOLUTION: Determine the values of θ if sinθ=-(square root3/2) and 0degrees≤θ≤360degrees and i know the answers are 240 degrees and 300 degrees What are the s

Algebra ->  Trigonometry-basics -> SOLUTION: Determine the values of θ if sinθ=-(square root3/2) and 0degrees≤θ≤360degrees and i know the answers are 240 degrees and 300 degrees What are the s      Log On


   

Question 939936: Determine the values of θ if sinθ=-(square root3/2) and 0degrees≤θ≤360degrees
and i know the answers are 240 degrees and 300 degrees
What are the steps in order to get these answers? do you use unit circle?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The sin is negative only in the 3rd and 4th quadrants,
so you are limited to those
+sin%28+theta+%29+=+-+sqrt%283%29+%2F+2+
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For a 30-60-90 triangle, the +sin%28+60+%29+=+sqrt%283%29+%2F+2+,
so one angle is +180+%2B+60+=+240+ in the 3rd quadrant
to make the sin negative
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The other angle whose sin is +-sqrt%283%29%2F2+ is
+360+-+60+=+300+ degrees in the 4th quadrant
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If you draw it, it's not confusing