SOLUTION: The length of a rectangle is 3 centimeters more than 3 times the width. If the perimeter of the rectangle is 46 centimeters, write a system of equations to describe this s

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Question 939648: The length of a rectangle is 3 centimeters more than 3 times the width. If the perimeter of the rectangle is 46 centimeters, write a system of equations
to describe this situation. Use the variable w to represent the width of the rectangle in the equations.
Found 2 solutions by stanbon, laoman:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
The length of a rectangle is 3 centimeters more than 3 times the width. If the perimeter of the rectangle is 46 centimeters, write a system of equations
to describe this situation. Use the variable w to represent the width of the rectangle in the equations.
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width:: w
length 3w+3
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Perimeter = 2(length + width)
46 = 2(3w+3 + w)
23 = 4w+3
4w = 30
w = 5 cm (width)
3w+3 = 18 cm (length)
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Cheers,
Stan H.
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Answer by laoman(51) (Show Source):
You can put this solution on YOUR website!
Ok, you just want a system of equation,
Given that the width should be w and let's represent the length by l,
From the first statement,l = 3*w + 3
Also, the perimeter of rectangle = 2*l + 2*w = 46
So your equations are and
QED