SOLUTION: Through (−1, −2);perpendicular to the line 2x + 5y + 1 = 0. What equation satisfies the conditions.

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Question 939539: Through (−1, −2);perpendicular to the line 2x + 5y + 1 = 0. What equation satisfies the conditions.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
2x + 5y + 1 = 0 0r y = (-2/5)x - 1/5
....
New Perpendicular Line: m = 5/2
***Using point-slope form, y+-+y%5B1%5D+=+highlight_green%28m%29%28x+-+x%5B1%5D%29P(-1,-2)
y + 2 = (5/2)(x+1)
y = (5/2)x + 5/2 - 4/2
y = (5/2)x + 1/2
0r
5x - 2y = -2 Standard Form