SOLUTION: the length of rectangle is 1cm less than twice the width. the perimeter is 28cm. find the dimensions of the rectangle.

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Question 939392: the length of rectangle is 1cm less than twice the width. the perimeter is 28cm. find the dimensions of the rectangle.
Answer by srinivas.g(540) About Me  (Show Source):
You can put this solution on YOUR website!
let x be the width of rectangle
the length of rectangle is 1cm less than twice the width
length = 2*x-1
perimeter = 28
formula: perimeter = 2(length+width)
28 = 2((2x-1)+x)
28 = 2(2x-1+x)
28 = 2(3x-1)
divide with 2 on both sides
28%2F2+=+2%283x-1%29%2F2
14++=+3x-1
add 1 on both sides
14+1 = 3x-1+1
15 = 3x
divide with 3 on both sides
+15%2F3+++=+3x%2F3
5+=x
width = 5 cm
length = 2*5 -1
= 10-1
= 9 cm
Length = 9 cm
Result : Dimensions: length = 9 cm & width = 5 cm