SOLUTION: kristin spent $131 on shirts.Fancy shirts costs $28 and plain shirts cost $15.if she bought a total of 7 then how many of each kind did she buy?

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: kristin spent $131 on shirts.Fancy shirts costs $28 and plain shirts cost $15.if she bought a total of 7 then how many of each kind did she buy?      Log On


   

Question 939299: kristin spent $131 on shirts.Fancy shirts costs $28 and plain shirts cost $15.if she bought a total of 7 then how many of each kind did she buy?
Answer by srinivas.g(540) About Me  (Show Source):
You can put this solution on YOUR website!
let x be the no of fancy shirts & y be the no of plain shirts
total no of shorts =7
x+y= 7.............eq(1)
Fancy shirts costs $28 and plain shirts cost $15
28*x+15*y =131....................eq(2)
Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
+system%28+%0D%0A++++1%5Cx+%2B+1%5Cy+=+7%2C%0D%0A++++28%5Cx+%2B+15%5Cy+=+131+%29%0D%0A++We'll use substitution. After moving 1*y to the right, we get:
1%2Ax+=+7+-+1%2Ay, or x+=+7%2F1+-+1%2Ay%2F1. Substitute that
into another equation:
28%2A%287%2F1+-+1%2Ay%2F1%29+%2B+15%5Cy+=+131 and simplify: So, we know that y=5. Since x+=+7%2F1+-+1%2Ay%2F1, x=2.

Answer: system%28+x=2%2C+y=5+%29.

Result : no of fancy shirts = 2
no of plain shirts = 5