SOLUTION: Two cars started from the same point, driving along the same road 20 seconds apart for ¼ of a mile to the store. The rate of the first car is 15 mph and the rate of the second car
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Question 939201: Two cars started from the same point, driving along the same road 20 seconds apart for ¼ of a mile to the store. The rate of the first car is 15 mph and the rate of the second car is 30 mph. which car will get to the store first? Found 2 solutions by TimothyLamb, lwsshak3:Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! a = time to the store of first car
b = time to the store of second car
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s = d/t
t = d/s
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time to the store of first car:
a = 0.25/15
a = 0.016666666666 hour
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time to the store of second car:
b = 0.25/30
b = 0.008333333333 hour
but the second car leaves 20 seconds after the first car:
b = 0.008333333333 hour + (20 seconds * 1/(60*60) hour/seconds)
b = 0.013888888888 hour
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answer:
the second car gets to the store first
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You can put this solution on YOUR website! Two cars started from the same point, driving along the same road 20 seconds apart for ¼ of a mile to the store. The rate of the first car is 15 mph and the rate of the second car is 30 mph. which car will get to the store first?
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travel time=distance/speed
let x=travel time of first car
let y=travel time of second car
..
1 hr=3600 sec
x=.25/15*3600=60 sec
y=.25/30*3600=30 sec
Second car gets to store first
First car took 40 more seconds to get to the store after the 20 second head start.
Second car only took 30 seconds to get to the store.
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