SOLUTION: A home is built on a 56 ft 9 in wide lot. The house is 5ft 5in from the side of the lot and is 34 ft 10 in wide. How far is the house from the other side of the lot? Need the answe

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: A home is built on a 56 ft 9 in wide lot. The house is 5ft 5in from the side of the lot and is 34 ft 10 in wide. How far is the house from the other side of the lot? Need the answe      Log On

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Question 939100: A home is built on a 56 ft 9 in wide lot. The house is 5ft 5in from the side of the lot and is 34 ft 10 in wide. How far is the house from the other side of the lot? Need the answer in inches
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
Remainder side = Total lot - house -other side
=(56 ft 9 in) - (34 ft 10 in) - (5 ft 5 in)
=(55 ft 21 in) - (34 ft 10 in) - (5 ft 5 in)
=16 ft 6 in
Convert to inches:
(16 ft x 12 in/ft)+ 6 in= Total in inches
192 in + 6 in= Total in inches
198 in= Total in inches
Check: One side + house + other side = Lot width
(5 ft 5 in)+(34 ft 10 in)+(16 ft 6 in)=Lot width
56 ft 9 in=Lot width, which equals the given.