SOLUTION: in a rhombus PQRS if PQ=3x-7 and QR=x+3 find PS

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Question 939055: in a rhombus PQRS if PQ=3x-7 and QR=x+3 find PS
Answer by srinivas.g(540) About Me  (Show Source):
You can put this solution on YOUR website!
In rhombus all sides are equal
PQ=QR
3x-7=x+3
Move-7 to the right
3x=x+3+7
3x=x+10
Move x to the left
3x-x=10
2x=10
Divide with 2 on both sides
2x%2F2=10%2F2
x=5
Hence PQ=3x-7
=3*5-7
=15-7
=8
Hence PQ=QR=RS=PS=8