SOLUTION: A canoe took 4 hours to travel 18 km with the current. On the return trip, the canoe took 6 hours to travel the same distance against the current. When the canoe travels with the c
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: A canoe took 4 hours to travel 18 km with the current. On the return trip, the canoe took 6 hours to travel the same distance against the current. When the canoe travels with the c
Log On
Question 939009: A canoe took 4 hours to travel 18 km with the current. On the return trip, the canoe took 6 hours to travel the same distance against the current. When the canoe travels with the current it travels faster than normal. How fast does the canoe travel with the current? One decimal accuracy. Answer by mananth(16946) (Show Source):
Distance against 18 miles distance with 18 km
t=d/r against current -
18.00 / ( x - y )= 6.00
6.00 ( x - y ) = 4.00
6.00 x - 6.00 y = 18.00 ....................1
18.00 / ( x + y )= 4.00
4.00 ( x + y ) = 18.00
4.00 x + 4.00 y = 18.00 ...............2
Multiply (1) by 4.00
Multiply (2) by 6.00
we get
24.00 x + -24.00 y = 72.00
24.00 x + 24.00 y = 108.00
48.00 x = 180.00
/ 48.00
x = 3.75 km/h
plug value of x in (1) y
6.00 x -6.00 y = 18.00
22.50 -6.00 -22.50 = 18.00
-6.00 y = 18.00
-6.00 y = -4.50 km/h
y = 0.75
canoe speed 3.75 km/h
current speed 0.75 km/h
With current speed = 3.75+0.75 = 4.5 km/h
m.ananth@hotmail.ca
