SOLUTION: Jim borrowed some money at 13% interest and some money at 16% interest. The amount at 16% was $200 more than twice the amount borrowed at 13%. How much was borrowed at each rate if

Let amount borrowed at 13% be T

Since the amount borrowed at 16% was $200 more than twice the amount borrowed at 13%, then amount borrowed

at 16% = 2T + 200

Annual interest paid on 13% loan = .13(T), or .13T

Annual interest paid on 16% loan = .16(2T + 200), or .32T + 32

As total annual interest paid was $234.5, we get: .13T + .32T + 32 = 234.5

.13T + .32T = 234.5 - 32

.45T = 202.5

T, or amount borrowed at 13% = , or $

Amount borrowed at 16% = 2(450) + 200, or 900 + 200, or $