SOLUTION: how many whole numbers leave no remainder when divided into 60.

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Question 938792: how many whole numbers leave no remainder when divided into 60.
Found 2 solutions by Edwin McCravy, MathLover1:
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
Rules:

1. Write the prime factorization of 60. [60 = 2²·3·5]
2. Look at the exponents in the prime factorization. [2, 1, 1]
3. Add 1 to each exponent. [(2 + 1), (1 + 1), (1 + 1)] 
4. Find the product of these numbers. [3·2·2 = 12]

Here are all 12:

1,2,3,4,5,6,10,12,15,20,30,60

Edwin

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

You can divide 60 by 1 and get an answer of 60 with no remainder. Likewise you can divide 60 by 60 and get an answer of 1 with no remainder. Most of the time the answers will be in pairs.
Here are all of the counting numbers that leave no remainder when divided into 60:

all divisors:
1 | 2 | +3+ | 4 | +5 | +6+ | +10 | 12 | 15 | 20 | 30 | 60 (12 divisors)
so, 12 whole numbers leave no remainder when divided into 60