Question 938672: An airplane left field A and flew on a course of 118degrees for 2 hours at 172mi/hr and landed at field B. It then took off on a course of 208degrees and landed at field C, which is due south of field A. How far is C from B?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! An airplane left field A and flew on a course of 118degrees for 2 hours at 172mi/hr and landed at field B. It then took off on a course of 208degrees and landed at field C, which is due south of field A. How far is C from B?
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Let field A be at (0,0)::
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Coordinates of B::
x-coordinate = 2*172*cos(118) = -161.5
y-coordinate = 2*172*sin(118) = 303.73
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Coordinates of C::
You did not post the time the plane flew from B to C.
If C is due south of A, it's x-coordinate = 0
Note:: A course of 208 degrees from B cannot get the plane due south of A.
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Cheers,
Stan H.
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