SOLUTION: Find two functions f(x) and g(x), such that h(x)=f(g(x)) when h(x)=1/(x^3-7x+2)

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Question 938436: Find two functions f(x) and g(x), such that h(x)=f(g(x)) when h(x)=1/(x^3-7x+2)
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Seeing a formal method would be an advantage.

f%28g%28x%29%29=1%2F%28x%5E3-7x%2B2%29

One possible function appears to be 1%2Fg. Based on that, another function should be g=x%5E3-7x%2B2.

Naming was uncertain at first trying to pick functions. Naming for g was picked after first trying to figure the function definitions occurring.
R=1/X, and W=x^3-7x+2 were like what first seemed to occur.

f%28x%29=1%2Fx, and g%28x%29=x%5E3-7x%2B2.