Question 938425: How would I use the elimination method to solve this problem?
2a+b=3
-3a-2b=-1
This is what I have so far
I multiply the first equation by -3 and the second equation by 2
So, I would have -6a+-3b=-9
-6a-4b=-2
-6a+-3b=-9
-6a-4b=-2
Both -6a would cancel out
1b=11
I am confused, I think I am misisng a step.
Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20849)   (Show Source):
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website! How would I use the elimination method to solve this problem?
2a+b=3
-3a-2b=-1
This is what I have so far
I multiply the first equation by -3 and the second equation by 2
So, I would have -6a+-3b=-9
-6a-4b=-2
-6a+-3b=-9
-6a-4b=-2
Both -6a would cancel out
1b=11
I am confused, I think I am misisng a step.
2a + b = 3 ------- eq (i)
-3a - 2b = -1 ------- eq (ii)
First of all, it doesn't make sense to multiply eq (i) by - 3 and eq (ii) by 2. It makes more sense to
multiply eq (i) by 3 and eq (ii) by 2. Then ADD the 2 new equations.
On the other hand, there's no need to multiplying both equations. You can simply multiply eq (i) by 2, and
then ADD the new equation to eq (ii). It's that simple. You'd then get the value of a, very, very easily.
Then you can find the value of b. Try it!!
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