SOLUTION: the square root of three times a certain number is subtracted from the number and the result is 6 . find the number

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Question 938345: the square root of three times a certain number is subtracted from the number and the result is 6 . find the number
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
the square root of three times a certain number is subtracted from the number and the result is 6 .
x+-+sqrt%283x%29+=+6
We can arrange it like this
x - 6 = sqrt%283x%29
square both sides
(x-6)^2 = 3x
x^2 - 12x + 36 = 3x
x^2 - 12x - 3x + 36 = 0
x^2 - 15x + 36 = 0
Factors to
(x-12)(x-3) = 0
Two solutions
x = 12
x = 3
:
Check both solutions in the original equation
12+-+sqrt%283%2A12%29+=+6
12 - 6 = 6, a good solution
and
3+-+sqrt%283%2A3%29+=+6
3 - 3 does not = 6, no solution
:
find the number x = 12