SOLUTION: The lengh of the diagonal in quadrilateral A is 5 sqrt(3) where 5 is the index, 3 is the radicand and the goal is to find the radical. the length of the diagonal in quadrilateral B

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Question 938243: The lengh of the diagonal in quadrilateral A is 5 sqrt(3) where 5 is the index, 3 is the radicand and the goal is to find the radical. the length of the diagonal in quadrilateral B is 8 sqrt (2) where 8 is the index and 2 is the radicant and your trying to find the radical. The length of the diagonal in quadrilateral C is 3 sqrt(12) where 3 is the index, 12 is the radicand and the goal is to get the radical... What is the approximate sum of the lengths of the diagonals of quadrilaterals A,B, and C? please explain how you find the radical.. That is what I am having trouble with. Thanks for your help!


ps pretty much if you didnt understand the question you just add the radicals of 5/-3 3/-12 8/-2 where /- equals a radical symbol

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
The length of the diagonal in quadrilateral A is 5sqrt%283%29+
the length of the diagonal in quadrilateral B is 8sqrt+%282%29
The length of the diagonal in quadrilateral C is 3sqrt%2812%29
3sqrt%2812%29->you can simplify this one:
3sqrt%284%2A3%29=>3sqrt%282%5E2%2A3%29=>3%2A2sqrt%283%29 =>6sqrt%283%29
What is the approximate sum of the lengths of the diagonals of quadrilaterals A,B, and C?
5sqrt%283%29+%2B8sqrt+%282%29%2B6sqrt%283%29
11sqrt%283%29+%2B8sqrt+%282%29 .....since sqrt%283%29=1.732050807568877 rounded sqrt%283%29=1.73 and sqrt+%282%29=1.414213562373095 rounded sqrt+%282%29=1.41, then
11%2A1.73+%2B8%2A1.41 .
19.03+%2B11.28
30.31-> your answer: the approximate sum of the lengths of the diagonals of quadrilaterals A,B, and C
ps:
when you need to type radicals here, type it this way:
three of these brackets {
then sqrt(a)
then close with three of these brackets }
if you need for example fourth root, you do it this way:
three of these brackets {
then root(4,a)
then close with three of these brackets }