SOLUTION: someone show me how to solve this?? If an observer is 200ft from a building and the angle of elevation to the top of a building is 60 degrees, what is the height of the building?ca
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Question 93817This question is from textbook algebra and trigonometry
: someone show me how to solve this?? If an observer is 200ft from a building and the angle of elevation to the top of a building is 60 degrees, what is the height of the building?can This question is from textbook algebra and trigonometry
You can put this solution on YOUR website! If an observer is 200ft from a building and the angle of elevation to the top of a building is 60 degrees, what is the height of the building?
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Draw the picture.
If the angle of inclination is 60 degrees and the building forms a right
triangle with the ground, the 3rd angle of the triangle formed is 30 degrees.
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The side opposite the 30 degree angle is (1/2) the hypotenuse.
That side opposite is 200 ft so the hypotenuse is 400 ft.
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Use Pythagoras to find the 3rd side of the right triangle which is the building.
400^2 = 200^2 + x^2
x^2 = 160000 - 40000 = 120000
x = 346.41 ft
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Cheers,
Stan H.
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