SOLUTION: sketch the straight line defined by the linear equation by finding x-and-y intercepts. -2x-6y+18=0

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Question 937944: sketch the straight line defined by the linear equation by finding x-and-y intercepts. -2x-6y+18=0
Found 2 solutions by mananth, KMST:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
GRAPH

4.00 3
-2 x + -6
y= - 1/ 3 x + 3

Assume values of x and plug in the equation to get values of y.
Plot the points
x 6 -6 8
y= 1 5 0.33




Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
-2x-6y%2B18=0<--->18=2x%2B6y
For x=0 , we get
18=2%2A0%2B6y --> 6y=18 --> y=18%2F6 --> highlight%28y=3%29
For y=0 , we get
18=2x%2B6%2A0 --> 2x=18 --> x=18%2F2 --> highlight%28x=9%29
That means that the x- and y-intercepts are points A%289%2C0%29 and B%280%2C3%29 .
Plotting those two points, and connecting them with a line,
you get to "sketch the straight line ... by finding x-and-y intercepts."