SOLUTION: find three consecutive odd positive integers such that 5 times the third integer equals three times the first integer plus seven more than the second integer

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Question 937828: find three consecutive odd positive integers such that 5 times the third integer equals three times the first integer plus seven more than the second integer
Found 3 solutions by CubeyThePenguin, MathTherapy, ikleyn:
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive odd integers: (x-2), x, (x+2)

5(x+2) = 3(x-2) + 7 + x
5x + 10 = 4x + 3
x = -7

The integers are -9, -7, and -5.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
find three consecutive odd positive integers such that 5 times the third integer equals three times the first integer plus seven more than the second integer
That person is WRONG, once AGAIN!!

Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
.

Let consecutive odd integers be (x-2), x, (x+2)

5(x+2) = 3(x-2) + 7 + x
5x + 10 = 4x + 1
x = -9

The integers are -11, -9, and -7, in ascending order.             ANSWER