SOLUTION: log base 4 (x+41)=log base 4 (2x+7)=3

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Question 937826: log base 4 (x+41)=log base 4 (2x+7)=3
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

+log+%284%2C+%28x%2B41%29%29=log+%284+%2C%282x%2B7%29%29+=3

+log+%284%2C+%28x%2B41%29%29=log+%284+%2C%282x%2B7%29%29+
+log+%284%2C+%28x%2B41%29%29%2Flog+%284+%2C%282x%2B7%29%29=0+
+log+%284%2C+%28x%2B41%29%2F%282x%2B7%29%29=0+
+log+%28%28x%2B41%29%2F%282x%2B7%29%29%2Flog+%284%29=0+
+log+%28%28x%2B41%29%2F%282x%2B7%29%29=0%2Alog+%284%29+
+log+%28%28x%2B41%29%2F%282x%2B7%29%29=0+ ...........we can write 0 aslog+%2810+%2C%281%29%29

+log+%28%28x%2B41%29%2F%282x%2B7%29%29=log+%2810+%2C%281%29%29+ ...if log same then

+%28x%2B41%29%2F%282x%2B7%29=1+ ...solve for x

+%28x%2B41%29=1%2A%282x%2B7%29

+41-7=2x-x

+x=34