SOLUTION: suppose you have a currency named miso in three denominations 1 miso , 50 miso and 10 miso. in how many ways can you pay a bill of 107 miso a) 16 b) 17 c)18 d)19 e)20

Algebra ->  Permutations -> SOLUTION: suppose you have a currency named miso in three denominations 1 miso , 50 miso and 10 miso. in how many ways can you pay a bill of 107 miso a) 16 b) 17 c)18 d)19 e)20       Log On


   



Question 937824: suppose you have a currency named miso in three denominations 1 miso , 50 miso and 10 miso. in how many ways can you pay a bill of 107 miso
a) 16
b) 17
c)18
d)19
e)20

Answer by Edwin McCravy(20062) About Me  (Show Source):
You can put this solution on YOUR website!
1 miso , 50 miso and 10 miso. in how many ways can you pay a bill of 107 miso
        x + 10y + 50z = 107

Since 107 ends in a 7 and 10y and 50z will have to end in a 0,
x must end in a 7, so x = 10k + 7

(10k + 7) + 10y + 50z = 107

      10k + 10y + 50z = 100

           k + y + 5z = 10

                k + y = 10 - 5z

if z = 0, then 

                k + y = 10 - 5(0)

                k + y = 10

k can be any integer from 0 to 10, inclusive, and y can
be chosen to make up the difference  That's 11 ways

if z = 1, then 

                k + y = 10 - 5(1)

                k + y = 5

k can be any integer from 0 to 5, inclusive, and y can
be chosen to make up the difference   That's 6 ways. 

                 if z = 2, then 

                k + y = 10 - 5(2)

                k + y = 0

k and y can only be 0.  That's 1 more way. 

Total number of ways:  11+6+1 = 18 ways.

FYI, here they all are:

 1.  107 ones.
 2.  1 ten  and 97 ones.
 3.  2 tens and 87 ones.
 4.  3 tens and 77 ones.
 5.  4 tens and 67 ones.
 6.  5 tens and 57 ones.
 7.  6 tens and 47 ones.
 8.  7 tens and 37 ones.
 9.  8 tens and 27 ones.
10.  9 tens and 17 ones.
11.  10 tens and 7 ones.
12.  1 fifty and 57 ones.
13.  1 fifty, 1 ten and 47 ones.
14.  1 fifty, 2 tens and 37 ones.
15.  1 fifty, 3 tens and 27 ones.
16.  1 fifty, 4 tens and 17 ones.
17.  1 fifty, 5 tens and 7 ones.
18.  2 fifties and 7 ones.

Edwin