SOLUTION: find the domain of the indicated function. Express answers in both interval notation and inequality notation. L(u) = √(3u^2 )+4

Algebra ->  Graphs -> SOLUTION: find the domain of the indicated function. Express answers in both interval notation and inequality notation. L(u) = √(3u^2 )+4      Log On


   

Question 937709: find the domain of the indicated function.
Express answers in both interval notation and inequality notation.

L(u) = √(3u^2 )+4
Found 2 solutions by MathLover1, lwsshak3:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
L%28u%29+=+sqrt%283u%5E2+%29%2B4
since we have a product 3u%5E2+ under radical sign,note that we cannot have a negative value under the square root sign or we will end up with a complex number, but u%5E2+ will give as positive value for all values of u whether is positive or negative number; whatever is under the root sign will be greater than or equal to 0 and we will have a solution
for u%5E2+=0=>L%28u%29+=+4, for other values of u%5E2+ we will have L%28u%29+
so, the domain is:
R (all real numbers)
(-infinity,infinity)
(-infinity%3C=u%3C=infinity)

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
find the domain of the indicated function.
Express answers in both interval notation and inequality notation.
L(u) = √(3u^2)+4
***
radican≥0
3u^2≥0
u^2>0
domain: all real numbers (-∞,∞)