Question 937607: Hello ma'am/sir, My name's Amanite and I've been having a hard time solving chemistry problems such as this... Please help me maam/sir and thanks in advance...
A chemist has a solution that is 50 percent acid. By adding water, the solution is reduced to one containing 40 percent acid. By adding 500 cubic centimeter more water, the solution then contains 35 percent acid. Determine: (a) how many cubic centimeters of the 50 percent acid solution the chemist had originally and (b) how many cubic centimeters of the 35 percent acid solution the chemist had finally.
Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website! A chemist has a solution that is 50 percent acid.-----------x cc 50%
By adding water, ...................y cc 0% acid
the solution is reduced to one containing 40 percent acid.40%(x+y)
50%x+0%y = 40%(x+y)
multiply by 100
50x= 40(x+y)
50x=40x+40y
10x= 40 y
y=1/4 x
The total solution now is (x+x/4) = 5x/4.............40%
40%*5x/4+500cc water*0% acid = 35%(5x/4 + 500)
multiply by 100
50x + 0 = (35(5x+2000)/4))
200x = 175x+70000
25x= 70000
x= 70000/25
x= 2800 cc
Check
2800*50%+3500*0 = z%(3500)
z=20%
Total solution = (5x/4 +500)
plug x
(5*2800/4 +500)
3500+500=4000 cc of final solution
By
|
|
|
