SOLUTION: I'm trying to make a mixed drink, called a johnny jump up. Its 15 oz . 14 oz of 20% alcohol cider... and 1 oz of Jameson.
But the issue is I don't have a 20% cider. I have a
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But the issue is I don't have a 20% cider. I have a
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Question 937592: I'm trying to make a mixed drink, called a johnny jump up. Its 15 oz . 14 oz of 20% alcohol cider... and 1 oz of Jameson.
But the issue is I don't have a 20% cider. I have a 50% alcohol apple jack and 5% alcohol angry orchard. What is the formula to mix these two liquors to come up with a solution that is roughly 20% in alcohol in mixture?
Thank you from a amateur mixologist who is racking his brain to try and figure out the math he forgot in school. Answer by jim_thompson5910(35256) (Show Source):
You want 14 oz of alcohol cider, so (since you mix those two to get 14 oz)
Solve for y to get
"I have a 50% alcohol apple jack and 5% alcohol angry orchard", so this means we have this equation . We have 0.5x oz of pure alcohol from the apple jack and 0.05y oz of pure alcohol from the angry orchard. These two amounts of pure alcohol will combine to be equal to 0.2*14 because you'll have 0.2*14 oz of pure alcohol (you want 20% of pure alcohol in the final mix)
We will use the equations and to find x & y. First we need to find x. So let's plug in into like so...