SOLUTION: Consider the point P = (2, 8) and the line L, given by the equation 6x - 3y = 15. A. Write an equation in slope-intercept of the line passing through P and parallel to line L.

Algebra ->  Linear-equations -> SOLUTION: Consider the point P = (2, 8) and the line L, given by the equation 6x - 3y = 15. A. Write an equation in slope-intercept of the line passing through P and parallel to line L.       Log On


   



Question 937545: Consider the point P = (2, 8) and the line L, given by the equation 6x - 3y = 15.
A. Write an equation in slope-intercept of the line passing through P and parallel to line L.
B. Write an equation in slope-intercept of the line passing through P and perpendicular to line L.
Please show all work including transforming from point slope toy-intercept, thank you!!!!

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Consider the point P = (2, 8) and the line L, given
by the equation 6x - 3y = 15.
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Given equation::
2x - y = 5
y = 2x-5
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A. Write an equation in slope-intercept of the line passing through P and parallel to line L.
P = (2, 8)
slope = 2
Form:: y = mx + b
Solve for "b"::
8 = 2*2 + b
b = 4
Equation:
y = 2x + 4
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B. Write an equation in slope-intercept of the line passing through P and perpendicular to line L.
slope = -1/2
y = mx + b
8 = (-1/2)2 + b
b = 9
Equation:
y = (-1/2)x + 9
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