SOLUTION: Willard can paint a room in 6 hours. His assistant can paint the same room in 8 hours. If Willard paints for 1 hour an then leaves, letting his assistant take over, how long will

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Willard can paint a room in 6 hours. His assistant can paint the same room in 8 hours. If Willard paints for 1 hour an then leaves, letting his assistant take over, how long will       Log On


   



Question 937419: Willard can paint a room in 6 hours. His assistant can paint the same room in 8 hours. If Willard paints for 1 hour an then leaves, letting his assistant take over, how long will it take the assistant to complete the job?
Found 2 solutions by josgarithmetic, TimothyLamb:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
RATES as JOB per HOUR
Willard, 1/6
Assistant, 1/8

"Completing the job" means, 1 whole job.

RT=J rate time job, basic uniform rates rule

The two do not work at this job simultaneously.
Willards time, 1 hour.
Assistant's time, x hours.

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(Best first step is to multiply left and right sides by 24).

Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
willard rate:
r = w/t
r = 1/6
---
fraction of job willard does in 1 hour:
w = rt
w = (1/6)*1
w = 1/6
---
fraction of job remaining:
w = 5/6
---
assistant rate:
r = w/t
r = 1/8
---
time for assistant to complete the job:
t = w/r
t = (5/6)/(1/8)
t = (5/6)*8
t = 40/6 hours
t = 6 and 2/3 hours
t = 6 hours and (2/3 hours * 60 minutes/hour)
t = 6 hours and 40 minutes
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