SOLUTION: A supertanker leaves port traveling north at an average speed of 10 knots. Two hours later a cruise ship leaves the same port, heading south at an average speed of 18 knots. How ma

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Question 937343: A supertanker leaves port traveling north at an average speed of 10 knots. Two hours later a cruise ship leaves the same port, heading south at an average speed of 18 knots. How many hours after the cruise ship sails will the two ships be 209 nautical miles apart? (1 knot = 1 nautical mile per hour)
Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
distance tanker had already traveled when the cruise ship sails:
s = d/t
d = st
d = 10*2
d = 20 nm
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relative speed of the two ships:
s = 10 + 18
s = 28 kts
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time after cruise ship sails, when the two ships are 209 nm apart ...
the two ships are already 20 nm apart when cruise ship sails:
d = 209 - 20
d = 189
t = d/s
t = 189/28
t = 6.75 hr
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