SOLUTION: I'm confused on how to do logs. the question is: log27x=2/3 Could you solve it step by step to help me better understand it please. Thanks, Bradley Whitt

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: I'm confused on how to do logs. the question is: log27x=2/3 Could you solve it step by step to help me better understand it please. Thanks, Bradley Whitt      Log On


   



Question 93731: I'm confused on how to do logs. the question is:
log27x=2/3
Could you solve it step by step to help me better understand it please.
Thanks,
Bradley Whittington
Lt. Governor, Division 18
Alabama District

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Comment:
"log" means "exponent" or "power"
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log27x=2/3
You are told "the exponent or power is 2/3"
You are also told that is 27 which has this exponent
Then you are told the result of applying that exponent of 27 is "x".
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So the exponential form of your problem is:
27^(2/3) = x
To solve this problem rewrite 27 as 3^3 to get:
[3^3]^(2/3) = x
Multiply the exponents to get:
x = 3^2
Simplify to get:
x = 9
==============
Hope this helps.
Remember: when you see the word "log" think "exponent".
Cheers,
Stan H.