SOLUTION: I am having some problems on this word problem A plane took 1 hr longer to travel 560 miles on the first portion of a flight than it took to fly 480 miles on the second portion.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I am having some problems on this word problem A plane took 1 hr longer to travel 560 miles on the first portion of a flight than it took to fly 480 miles on the second portion.      Log On


   

Question 93725: I am having some problems on this word problem
A plane took 1 hr longer to travel 560 miles on the first portion of a flight than it took to fly 480 miles on the second portion. If the speed was the same for each portion, what was the flying time for the second part of the trip?
Thank you
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A plane took 1 hr longer to travel 560 miles on the first portion of a flight than it took to fly 480 miles on the second portion. If the speed was the same for each portion, what was the flying time for the second part of the trip?
:
Let's just reason it out:
:
The problem requests the flying time of the 2nd part, therefore:
Let x = time for the 2nd part of the trip
:
It said,
"plane took 1 hr longer to travel 560 miles on the first portion of a flight::
therefore:
(x + 1) = time for the 1st part of the trip
:
Speed was given as the same for each portion, so we can write a speed equation:
Speed = Dist/time
:
1st part speed = 2nd part speed
560%2F%28%28x%2B1%29%29 = 480%2Fx
:
Cross multiply and we have:
560x = 480(x+1)
:
560x = 480x + 480
:
560x - 480x = 480
:
80x = 480
:
x = 480/80
:
x = 6 hrs is the time of the 2nd part
:
:
Check our solution to find out if, indeed, the speeds are the same.
1st part took 1 hr longer, 7 hrs.
:
560/7 = 480/6
80 = 80; confirms our solution
;
Did this make sense to you? Any questions?