SOLUTION: the length of a rectangle is 4 times its width and the perimeter is 150 feet.
What is the width of the rectangle?
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-> SOLUTION: the length of a rectangle is 4 times its width and the perimeter is 150 feet.
What is the width of the rectangle?
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You can put this solution on YOUR website! x = L
y = W
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x = 4y
2x + 2y = 150
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put the system of linear equations into standard form
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x - 4y = 0
2x + 2y = 150
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = L = 60 ft
y = W = 15 ft
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