SOLUTION: The intensity of light on the plane surface varies inversely as the square of the distance from the source of light. you're reading the book 5 feet from an electric light. if you

Algebra ->  Expressions-with-variables -> SOLUTION: The intensity of light on the plane surface varies inversely as the square of the distance from the source of light. you're reading the book 5 feet from an electric light. if you      Log On


   



Question 937182: The intensity of light on the plane surface varies inversely as the square of the distance from the source of light. you're reading the book 5 feet from an electric light. if you move one foot closer how many times greater is the intensity of light in the book?
Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
i = C/dd
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intensity at original position:
a = C/25
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intensity one foot closer to light:
b = C/16
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ratio of intensities:
b/a = (C/16)/(C/25)
b/a = (1/16)/(1/25)
b/a = 25/16
b/a = 1.5625
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answer:
1.5625 times greater
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