SOLUTION: solve for x if 2log3.45+2log x=7

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: solve for x if 2log3.45+2log x=7      Log On


   

Question 937165: solve for x if 2log3.45+2log x=7
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

2log%28%283.45%29%29%2B2log+%28%28x%29%29=7

log%28%283.45%5E2%29%29%2Blog+%28%28x%5E2%29%29=7

log%28%283.45%5E2%2Ax%5E2%29%29=7

log%28%283.45%5E2%2Ax%5E2%29%29%2Flog%28%2810%29%29=7

log%28%283.45%5E2%2Ax%5E2%29%29=7log%28%2810%29%29

log%28%283.45%5E2%2Ax%5E2%29%29=log%28%2810%5E7%29%29....if log same, then

3.45%5E2%2Ax%5E2=10%5E7

x%5E2=10%5E7%2F3.45%5E2

x%5E2=10000000%2F11.9025

x%5E2=840159.6303297626549044318420499894980046208779668136946019743

x%5E2=+sqrt%28840159.6303297626549044318420499894980046208779668136946019743%29

x=916.6022203386606759417082737486140677447985911087585005384071 round it

x+=+916.602
if you check this solution you will get 2log%28%283.45%29%29%2B2log+%28%28+916.602%29%29=7.000000
if you round it to one decimal place,x+=+916.6, you will get 2log%28%283.45%29%29%2B2log+%28%28+916.6%29%29=6.999998