SOLUTION: The perimeter of a rectangle is 38 cm and its area is 60 cm2. Let x be the width of the rectangle. Find the dimensions of the rectangle.
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Question 937158: The perimeter of a rectangle is 38 cm and its area is 60 cm2. Let x be the width of the rectangle. Find the dimensions of the rectangle. Answer by dkppathak(439) (Show Source):
You can put this solution on YOUR website! The perimeter of a rectangle is 38 cm and its area is 60 cm2. Let x be the width of the rectangle. Find the dimensions of the rectangle.
solution let length is l and breath is b
P =2(l+b)
38=2(l+b) l+b =19 (!) or l=19-b
area lb=60 (2) by substituting the value of l in (2)
(19-b)b=60
19b-b^2=60
b^2 -19b +60 =0
b^2-15b-4b+60 =0
(b-4)(b-15) =0
so b=4 or b=15 and l=4 or l=15
so dimensions are 4 and 15 cm
