SOLUTION: 49x exponent8 - 35x exponent6 - 56x exponent3 over 7x exponent3

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Question 93710This question is from textbook Beginning Algebra
: 49x exponent8 - 35x exponent6 - 56x exponent3 over
7x exponent3 This question is from textbook Beginning Algebra

Found 2 solutions by Earlsdon, jayanthihemkos@yahoo.com:
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Simplify:
%2849x%5E8-35x%5E6-56x%5E3%29%2F7x%5E3 Factor 7x%5E3 from the numerator.
cross%287x%5E3%29%287x%5E5-5x%5E3-8%29%2Fcross%287x%5E3%29 Cancel the indicated factors.
7x%5E5-5x%5E3-8

Answer by jayanthihemkos@yahoo.com(87) About Me  (Show Source):
You can put this solution on YOUR website!
49x exponent8 - 35x exponent6 - 56x exponent3 over
7x exponent3
49x^8 -35x^6-56x^3/7x^3

Take 7x^3 as common factor
7x^3(7x^5 - 5x^3 - 8)/7x^3
7x^3 in the numerator and denominator is cancelled
7x^5 - 5x^3 - 8
Hence the solution