SOLUTION: Two cars, one traveling 10 mph faster than the other car, start at the same time from the same point and travel in opposite directions. In 3 hours they are 300 mi apart. Find the r
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Question 937095: Two cars, one traveling 10 mph faster than the other car, start at the same time from the same point and travel in opposite directions. In 3 hours they are 300 mi apart. Find the rate of each car. Found 2 solutions by TimothyLamb, Danielshinmath:Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! x = speed of faster car
y = speed of slower car
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x = y + 10
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s = d/t
s = 300/3
s = 100
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speed of cars relative to each other:
s = x + y
s = y + 10 + y
s = 2y + 10
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equate s's:
2y + 10 = 100
2y = 90
y = 45
x = 55
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answer:
x = speed of faster car = 55 mph
y = speed of slower car = 45 mph
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You can put this solution on YOUR website! This means the faster car will go 30 miles total more than the slower car. So that means the slower car + the faster car=300. Th faster car is 30 +the slower car, so it is 2(slower car)+30=300 so that means 2 times the slower car is 270. But they have driven 3 hours, so each car goes 45mph and 45+10=55mph.
ANSWER:45mph and 55mph
