SOLUTION: (3^4)(3^-2) (5^2)^3 (2/3)^3 8^4-8^6 (7^6)(7^-6)

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: (3^4)(3^-2) (5^2)^3 (2/3)^3 8^4-8^6 (7^6)(7^-6)      Log On


   

Question 936733: (3^4)(3^-2)
(5^2)^3
(2/3)^3
8^4-8^6
(7^6)(7^-6)
Answer by oscargut(2103) About Me  (Show Source):
You can put this solution on YOUR website!
(3^4)(3^-2) = 3^2 = 9
(5^2)^3 = 5^6
(2/3)^3 = 2^3/3^3 = 8/27
8^4-8^6 = can you clarify this one ?
(7^6)(7^-6) = 7^0 = 1
If you need more help or details you can contact me at:
mthman@gmail.com
Thanks