SOLUTION: Solve the system (everything in this is logs not exponents) : {3x-y=6}{xy=24} There are two solutions: (x1, y1) and (x2, y2). Evaluate x1+y1+x2+y2= A. 8 B. 0 C. 8+6 sqrt3 i D

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Solve the system (everything in this is logs not exponents) : {3x-y=6}{xy=24} There are two solutions: (x1, y1) and (x2, y2). Evaluate x1+y1+x2+y2= A. 8 B. 0 C. 8+6 sqrt3 i D      Log On


   

Question 936711: Solve the system (everything in this is logs not exponents) : {3x-y=6}{xy=24}
There are two solutions: (x1, y1) and (x2, y2). Evaluate x1+y1+x2+y2=
A. 8
B. 0
C. 8+6 sqrt3 i
D. -4
E. none of these
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
3x-y=6
y=3x-6
.
.
xy=24
x%283x-6%29=24
x%28x-2%29=8
x%5E2-2x=8
x%5E2-2x-8=0
%28x-4%29%28x%2B2%29=0
Two solutions:
x-4=0
x%5B1%5D=4
Then,
4y=24
y%5B1%5D=6
and
x%2B2=0
x%5B2%5D=-2
Then,
-2y=24
y%5B2%5D=-12
So then,
x%5B1%5D%2By%5B1%5D%2Bx%5B2%5D%2By%5B2%5D=4%2B6-2-12=highlight%28-4%29