SOLUTION: a plane takes off and travels at an angle of 40 degrees north of east at 110 mph for 2 hours. it then adjusts its path to head 10 degrees west of north and travels in that directio
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Question 936688: a plane takes off and travels at an angle of 40 degrees north of east at 110 mph for 2 hours. it then adjusts its path to head 10 degrees west of north and travels in that direction for half an hour at a speed of of 100 mph. Approximately how far was the plane from its starting point? Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! s = d/t
d = st
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first leg distance:
b = 110*2 = 220 miles
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second leg distance:
c = 100*1/2 = 50 miles
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angle A between legs b and c:
40 + 80 = 120 degrees
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use The Law of Cosines to find side a, the third side of the triangle:
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aa = bb + cc - 2bc cosA
aa = 220*220 + 50*50 - 2*220*50*cos(120)
a = sqrt( 220*220 + 50*50 - 2*220*50*cos(120) )
a = 248.797106092
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answer:
249 miles
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